Mark M. answered 10/03/21
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = 3xe-x
The graph is concave down when f"(x) < 0.
f'(x) = 3e-x - 3xe-x = 3e-x(1 - x)
f"(x) = -3e-x - 3e-x(1 - x) = -3e-x(2 - x) = 0 when x = 2.
If x < 2, then f"(x) < 0. So, the graph of y = f(x) is concave down.
If x > 2, then f"(x) > 0. So, the graph of y = f(x) is concave up.
The graph of y = f(x) is concave down on the interval (-∞, 2).