Ryan G. answered 10/04/21
Math, physics and astronomy tutor
So x(t) = t3 - 4t.
Taking the derivative once, gives the velocity v(t) = 3t2 - 4.
For the acceleration, take the derivative one more time, a(t) = 6t
Setting the velocity equation equal to zero gives 3t2 = 4 and so velocity is zero at t = 2/√3. The acceleration at this time is 6*2/√3.
The acceleration is zero only at t = 0. The velocity at this time is -4