Finite Math Help!

Question

A pharmaceutical company has two drug trials coming up. For the first trial, they project a 60% success rate. For the second trial, however, they project a 45% success rate. Based on these predictions what is the probability that both trials will be failures?   *Round your answer to the third decimal place.

Answer 1

P(Failure) = 1 - P(Success) 

 

For independent events A and B, P(A and B) = P(A)*P(B) 

 

P(First trial fails) = 1 - 0.6 = 0.4

P(Second trial fails) = 1 - 0.45 = 0.55

 

P(Both trials fail) = 0.4*0.55 = 0.22 = 22%