
Brandon G.
asked 10/01/21Derivatives of Inverse Functions
y = arctan (√3x2-1)
y =
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1 Expert Answer
Mark M. answered 10/02/21
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
y = arctan√(3x2-1)
y' = 1 / [1 + (√(3x2-1)2] (√(3x2-1)' = 1/(3x2) [(1/2)(3x2-1)-1/2(6x) = 1 / [x√(3x2-1)]
Brandon G.
Thank you so much Mark!
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10/02/21
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Paul M.
10/02/21