Chloe Z. answered 10/01/21
Rice University Mathematics MA with 7 Years Teaching Experience
If a set of two vectors is a linearly independent set, then the vectors can’t be multiples of each other. Assume u and v are linearly independent.
- the second vector 4u+4v=4(u+v), which is a multiple of the first vector. Hence the set is not linearly independent.
- 6u and 6v are not multiples of each other assuming u and v are not multiples of each other. Hence the set is linearly independent.
- the zero vector is a multiple of any vector, because any vector times zero is zero, so the set is not linearly independent.
- Assume u+v is a multiple of u, then there should be a scalar b such that u+v=b*u, this implies (1-b)*u=v, which implies v is a multiple of u, which can’t be true because u and v are linearly independent. So this set is also linearly independent.