Raymond B. answered 10/01/21
Math, microeconomics or criminal justice
y=2x-3
f'(2) = 2 = the slope of the tangent line
at x=2 y=f(x)= f(2) = 1
y=2x - 3 = 2(2)-3 = 4-3 = 1
Pauline Y.
asked 09/30/21Given that 𝑓′(2)=2 and 𝑓(2)=1 , find the equation of the tangent line to the curve 𝑦=𝑓(𝑥) at 𝑥=2.
Group of answer choices
Raymond B. answered 10/01/21
Math, microeconomics or criminal justice
y=2x-3
f'(2) = 2 = the slope of the tangent line
at x=2 y=f(x)= f(2) = 1
y=2x - 3 = 2(2)-3 = 4-3 = 1
Mark M. answered 09/30/21
Mathematics Teacher - NCLB Highly Qualified
At (2, 1) the slope of the tangent is f'(2) = 2.
Use point-slope form from Algebra 1.
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