Matt C. answered 09/29/21
PhD Prof from U Chicago Specializing in Calculus
1) If f is even, then f(-1) = f(1), which means f cannot be one-to-one. So the statement is TRUE.
2) If f is odd, f is not necessarily one-to-one. For example, the function f(x) = 0 is odd, but not one-to-one. So the statement is FALSE.