λ(λ + 2) - (2)(1) = 0
So, λ2 + 2λ - 2 = 0
λ = [-2 ± √12] / 2 = [-2 ± 2√3] / 2 = -1 ± √3
Rodrigo M.
asked • 09/29/21Find the value of 𝜆 that makes the determinant 0. | 𝜆 +2 2| second-row -> |1 𝜆 |
Find the value of 𝜆 that makes the determinant 0. | 𝜆 +2 2|
| 1 𝜆 |
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