
Mark M. answered 09/28/21
Tutor
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(278)
Mathematics Teacher - NCLB Highly Qualified
2 = 18(0.5)t/14
Can you solve for t using logrithms?
Pauline Y.
asked 09/28/21The half-life of phosphorus-32 is about 14 days. There are 18 grams present initially. When will there be 2 grams remaining (in days)?
Mark M. answered 09/28/21
Mathematics Teacher - NCLB Highly Qualified
2 = 18(0.5)t/14
Can you solve for t using logrithms?
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Pauline Y.
would t=4409/29/21