Please Help. Thank you and Godbless.

Question

State the coordinates of the intercepts, stationary points, and the inflection point of p(x) = x (x^2-1)^2?

a. Number of x-intercepts give the x,y coordinates:

b. y-intercept: (?,?)

Answer 1

Hi,

p(x) = x (x^2-1)^2?

For finding x- int and y-int you need to know: #1 y=0 then find x & #2 x=0 then find y

#1 y= 0 ====> p(x) =0 then you need to solve this equation x (x^2-1)^2=0

x (x^2-1)^2=0 ===> x = 0 & (x^2-1)^2=0=====> (x^2-1)=0 ====> x^2=1 after taking root of both sides

You will have x = ± 1

so (0,0) (1,0) (-1,0) are y-int in this case you have (0,0) so it means the graph must through of origin and #2 it is not necessary.

I hope it is useful,

Minoo