y = (3x2ex) / (9x + 1)
Using the quotient rule we have:
y' = ((9x + 1)(3x2ex + 6xex) - 9(3x2ex))/(9x + 1)2
y' = (27x3ex + 54x2ex + 3x2ex + 6xex - 27x2ex)/(9x + 1)2
y' = (27x3ex + 30x2ex + 6xex)/(9x + 1)2
y' = 3xex(9x2 + 10x + 2)/(9x + 1)2
Alex M.
asked 09/27/21y = (3x2ex) / (9x + 1)
y = (3x2ex) / (9x + 1)
Using the quotient rule we have:
y' = ((9x + 1)(3x2ex + 6xex) - 9(3x2ex))/(9x + 1)2
y' = (27x3ex + 54x2ex + 3x2ex + 6xex - 27x2ex)/(9x + 1)2
y' = (27x3ex + 30x2ex + 6xex)/(9x + 1)2
y' = 3xex(9x2 + 10x + 2)/(9x + 1)2
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