
Raphael K. answered 09/21/21
I genuinely love teaching Calculus and have for 10+ years.
Odd and Even functions
if f(x) is a odd function, which of the following must be an even function
a) 2·f(x)
b) x2+f(x)
c) x+f(x)
d)x2·f(x)
e) x·f(x)
Odd functions exist when f(-x) = -[f(x)]
Or basically when you substitute x with -x in the function, if you arrive at the negative of the equation after simplifying. Then it is an odd function. Remember: Odd function are symmetric about the origin.
Even functions exist when f(-x) = f(x)
Or basically when you substitute x with -x in the function, and you arrive at the same equation after simplifying. Then it is an even function. Remember: Even functions are symmetric about the y-axis.
So:
a) 2 - f(x) is an odd function shifted up units two and reflected over x-axis, not even
b) x2+f(x) even function plus and odd function, not even
c) x+f(x) odd + function, still odd
d) x2·f(x) even times odd is still odd because adding 2 two a 3 = 5, still odd
e) x·f(x) odd times odd = even, example: x3 * x5 = x8 (even)
Answer: e) x·f(x)