f'(x)=5xcos x -4sin x
I will leave it to you to substitute x=-pi/4.
Correction:
f'(x)=5xcos x + 5sinx-sin x = 5xcos x +4sin x
Brandon G.
asked • 09/19/21Derivatives of Trigonometric Functions
f(x) = 5x(sinx) + cosx
f '(x) =
f '(−π/4) =
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Brandon G.
How did you get the 4?09/21/21