Determine all values of h and k for which the system has no solution.

Question

−3x-3y=h

-4x+ky=-1

k = ?

h ≠ ?

Answer 1

Multiply the first equation by 4 and the second by -3:

-12x - 12y = 4h

12x - 3ky = 3

Add the equations:

(-12 - 3k)y = 4h + 3

No solution if -12 - 3k = 0 and 4h + 3 ≠ 0

k = 4 and h ≠ -3/4