The Derivative as a Function

Question

Given that f(-4) = -8 and f '(-4) = 3  find an equation for the tangent line to the graph of y = f(x) at x = -4

y =

Answer 1

Given that the function passing the point (-4, -8) with tangent line slope of 3 at x=-4

The tangent line equation is

y = 3(x--4) -8 = 3x+12 -8 = 3x+4 using point slope form

Therefore

y=3x+4

Answer 2

Use point-slope form from Algebra 1.