Mark M. answered 09/12/21
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
The functions are continuous so we can evaluate the limits by plugging in.
For the first one, we have (π/4)cos2(π/4) = (π/4)(√2/2)2 = π/8
For the other problem, we get cos(0 + sin0) = cos(0) = 1