Gwen R. answered 03/08/15
Tutor
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Let x be the weight of the first table, x/2 is the second, the third x/6
x+.5x + .167x = 16.9
1.667x = 16.9
10.14 pounds is the weight of the first, 5.07 pounds is the weight of the second, 1.69 pounds is the weight of the third
OR
Let y be the weight of the second table, and 2y be the first, and y/3 the third
y +2y+y/3 = 16.9 Multiply all terms by 3 to eliminate the fraction
3y +6y+y = 50.7
10y = 50.7
y= 5.07 pounds second table, 10.14 pounds first table, 1.69 pounds is the weight of the third table