Statistics and Probability

Question

In a recent year, 8,090,845 male students and 1,841,009 female students were enrolled as undergraduates. Receiving aid were 64.3% of the male students and 69.9% of the female students. Of those receiving aid, 43% of the males got federal aid and 54.4% of the females got federal aid. Choose 1 student at random.

(Hint: Make a tree diagram.) Find the probability of selecting a student from the following.

Carry your intermediate computations to at least 4 decimal places. Round the final answers to 3 decimal places.

a. A female student with aid.

b. A male student, given that the student has aid.

c. A female student or a student who receives aid.

Answer 1

All of these can be solved by figuring out how many of the students qualify for criteria in a and c and then divide by the total number (8090845+1841009) or if a subgroup is specified as a given, you divide by that number.(b)

a) Number of females with aid: 1841009(.699) and total number

b) Number of students that have aid: 8090845*.643 + 1841009*.699

Number of male students with aid 8090845*.643

c) The number of students that are female or who receive aid is equal to the number of females + the number of male students with aid. Add those (we've already got those numbers) and divide by total number of students

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