which equation represents a line which is perpendicular to the line 7x - 8y = 16

Answer 1

"Which equation represents a line which is perpendicular to the line 7x - 8y = 16?"

To do this, we must recall that two lines are perpendicular if their slopes are negative reciprocals of each other. That is, if line A has a slope of r/s, then line B must have a slope of -s/r.

First, we must rewrite the above equation in slope-intercept form from standard form. To do this, we must solve for y in terms of x and other constants:

7x - 8y = 16

-8y = -7x + 16

y = (7/8)x - 2

The slope of the above line is 7/8, therefore the slope of a perpendicular line must be -8/7.

Therefore, the equation of any perpendicular line must be y = (-8/7)x + B, where "B" is the y-intercept of the line.