Raymond B. answered 08/20/21
Math, microeconomics or criminal justice
C(x) = .03x^3 - 5x + 300
Marginal Cost = C'(x)= .09x^2 -5
C'(30) = .09(30^2) -5 = 81-5 = 76
C(30) = .03(30^3)-5(30) +300 = 810 -150+300 = 960
C(31) = .03(31^3) -5(31) +300 = 893.73 -155+300= 1038.73
C(31) - C(30) = 1038.73 - 960 = 78.73
which appears to be different from Marginal Cost = C'(30) =76
but take the average of C'(30) and C'(31) = (76+81.49)/2 = 78.745 which is fairly close to 78.73 within 1.5 hundredth
C'(30.5) = .09(30.5)^2 -5 = 78.7225 is even closer, within .0075 or within 0.75 hundredth
C(31)-C(30) is the marginal cost over an interval
C'(30.5) is the marginal cost at a point. The smaller the interval the closer C'(x) is to the difference in total cost.