algebra problem

Question

A weight hangs on a spring. The vibration period of that weight is the time in which it makes a complete cycle in motion. Suppose the relationship between the vibration period "T" (in seconds) and the weight "w" (in kilograms) is given by T = 2π√(w / 200). Find the period T, to the nearest thousandth, for a spring with a hanging weight of 2.0 kilograms.

Answer 1

Answer:

T = 2π √ ( W / 200) where W = 2 kg if the √ ( W / 200) gives time in seconds then √( 2kg/200) = √0.01 s = 0.1 s

T = 2π( 0.1 s) = 0.2π s = 0.2( 3.1416) s = 0.628 s