
Afreen K.
asked 07/23/21hw 5 question 5
Using the first derivative, find the interval(s) for which f(x) is increasing and decreasing.
f(x) = 12 + 9x - 3x^2 - x
1 Expert Answer
Since f(x) = 12 + 9x - 3x^2 - x, then f'(x) = 0 + 9 - 3*2x - 1 = 8 - 6x, so
f(x) is increasing when f'(x) = 8 - 6x is > 0, so let's solve that for x:
8 > 6x, so 8/6 > x, so 4/3 > x, so x < 4/3, and
f(x) is decreasing when f'(x) = 8 - 6x is < 0, so let's solve that for x:
8 < 6x, so 8/6 < x, so 4/3 < x, so x > 4/3, so finally we have:
f(x) is increasing on (-∞, 4/3), and f(x) is decreasing on (4/3, ∞)
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Mark M.
Check the accuracy of f(x).07/24/21