
William W. answered 07/21/21
Experienced Tutor and Retired Engineer
Assuming the functions have "t" represented as seconds:
E = 0∫0.01 (20e-100t)(2 - e-100t) dt
E = 0∫0.01 (40e-100t - 20e-200t) dt
E = [(40/-100)e-100t - (20/-200)e-200t] evaluated between 0 and 0.01
E = [-0.4e-100t + 0.1e-200t] evaluated between 0 and 0.01
E = [-0.4e-100(0.01) + 0.1e-200(0.01)] - [-0.4e-100(0) + 0.1e-200(0)]
E = [-0.4e-1 + 0.1e-2] - [-0.4 + 0.1]
E = [-0.4/e + 0.1/e2] - [-0.3]
E = -0.14715 + 0.01353 + .3
E = 0.166 joules