Jacob C. answered 07/21/21
Adaptive Math and Physics Tutor
The current is the time rate of change of the electric charge - I = dQ/dt. We can write the charge differential dQ as I(t) dt such that integrating over the charge differential will yield the total charge Q = ∫ dQ = ∫ I(t) dt. Integrating from t = 1 to t = 4:
Q = ∫14 I(t) dt
Q = ∫14 t-1/2 dt
Q = 2t1/2 |14
Q = 2(4)1/2 - 2(1)1/2
Q = 2(2) - 2(1)
Q = 2 C