How to write point one=(0,-2) and point two=(-3,-5) in slope-intercept form?

Answer 1

Slope-intercept form is y = mx + b where m is the slope and b is the y-intercept. Since you were given two points on the line, we can compute the slope as m = (y₂ - y₁)/(x₂ - x₁):

m = (y₂ - y₁)/(x₂ - x₁)

m = (-5 - (-2))/(-3 - 0)

m = (-5 + 2)/(-3)

m = (-3)/(-3)

m = 1

Then, the equation of the line becomes y = (1)x + b, or simply y = x + b. We use one of the points on the line to determine the y-intercept, b, simply by substitution of the corresponding values of x and y. We'll use the point (0, -2) such that:

y = x + b

-2 = 0 + b

-2 = b

Thus, the equation of the line is y = x - 2.