Slope=-4 and Point=(2,-4) how to write it in slope-intercept form?

Answer 1

If a straight line passes through point (2,- 4) and has a slope of - 4, we can use the point-slope formula:

y - y₁ = m (x - x₁)

to get it into slope-intercept form, which is:

y = m x + b.

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Step 1: First, plug in what we know into the point-slope form:

knowns:

x₁ = 2

y₁ = - 4

m (slope) = - 4

point-slope form:

y - y₁ = m (x - x₁)

y - (- 4) = - 4 (x - 2)

Step 2: Distribute the -4 on the right hand side

y - (-4) = -4x + 8

**don't forget to watch your negative signs/distribute the negative

we can also adjust the left hand side of the equation since we know "y" minus a negative 4 is the same as adding 4.

y + 4 = -4x + 8

Step 3: Subtract 4 from both sides to isolate the y on the left hand side

y + 4 - 4 = -4x + 8 - 4

which gives us the solution:

ANSWER:

y = -4x + 4

which is in point-slope form.

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Good luck! Hope this explanation helps :)

-Hillary