Katya S. answered 07/14/21
Math. Pre-/ Algebra, Trigs, Pre-/ Calculus, Geometry. IT & Russian.
∝1st : d/(dx)(sin(x) - cos(x)) = sin(x) + cos(x)
Increasing : f'(x) > 0 ⇒ Periodical intervals (-π/4 + 2πk, 3π/4+2πk)
Decreasing on the others.
2nd: (d^2)/(dx^2)(sin(x) - cos(x)) = -sin(x) + cos(x)
Concave up : f''(x) > 0 ⇒ f'(x) is increasing ⇒ Periodical intervals (-3π/4 + 2πk, π/4 + 2πk)
Concave down on the others.
6. Since it has a vertical asymptote at x = 2, check for a horizontal asymptote, which is y=1 because both powers of x, in numerator and denominator, are the same with coefficients 1 and 1, 1/1 = 1.
You have to specify intervals because this is what you get:
f'(x) = -5/(x - 2)^2 which is negative on anything but x = 2, i.e. you function always decreases.
on x∈ (-∞,2) f(x)∈ (1,-∞) and on x∈ (2,∞) f(x)∈ (∞,1)