Tom N. answered 07/12/21
Strong proficiency in elementary and advanced mathematics
∇f(x,y) = fxi +fyj where fx = 3sin(xy) +3xycos(xy) fy= 3x2cos(xy).Then ∇f =3(sinxy +xycosxy)i +3x2cosxyj . At the point (3,1) ∇f = 3(sin3 + 3cos3)i + 27cos3j so ∇f = 3(.1409 -2.97)i - 26.7j = -8.876i -26.7j. |∇f| =(78.795 +712.89)1/2 = 28.137. The unit vector is (-8.876i - 26.7j)/ 28.137.