Nick S. answered 07/08/21
Top 100 Tutor Nationwide for 2013, tutoring Calculus for 30+ years
Pi = 3.14
2(Pi)r + h = 105 in => h = 105 - 2(Pi)r
V = (Pi) r2h => V= (Pi) r2 * [ 105 - 2(Pi)r ] = 105 (Pi) r2 - 2(Pi)2r3
dV/dr = 210(Pi)r - 6 (Pi)2 r2 = 0 => 6(Pi)r [35 - (Pi)r] = 0 =>
r=0 which is irrelevant.
Or
[35 - (Pi)r] = 0 => 35 = (Pi)r => r= 35/(Pi) in =>
h=105 -2(Pi) [35/(Pi)] = 105 - 70 = 35 in