
Bradford T. answered 07/05/21
Retired Engineer / Upper level math instructor
s(t) =-7t2+70t
s(1) = -7+70 = 63
s(5) = -175+350=175
s(4) = 168
s(3) = 147
a) Vavg = (s(5)-s(1))/(5-1) = (175-63)/4 = 28
b) Vavg =(s(4) - s(1))/(4-1) = (168-63)/3 = 35
c) Vavg= (s(3)-s(1))/((3-1) = (147-63)/2 = 42
d)
Vavg(h) = (s(1+h)-s(1))/(1+h-1) = (-7(1+h)2+70(1+h)+7 - 70)/h
= 56-7h
Notice that if h = t1-t0
V(4) = 28, same as (a)
V(3)= 35, same as (b)
V(2)=42, same as (c)