One urn contains 4 white balls, 4 black balls, and 4 red balls. 6 balls are removed from that urn. Determine the probability of 2 balls of each color being drawn.

Answer 1

C(4,2) * C(4,2) * C(4,2)/C(12,6)

where C(x,y) is number of combinations of x items, taken y at a time = x!/(y!(x-y)!)