Alex L. answered 07/01/21
Experienced and licensed math educator w/ practical statistics exp.
We'll put C in terms of one other variable and either graph it or find a derivative to minimize.
S, T, and U are positive and C is their sum so also positive. Thus S, T, and U will each be as small a positive number as possible, so I'm going to assume S+U=100 and 2S+T=50 for this minimum.
Rearrange: U=100-S and T=50-2S
Substitute: C=2S + (50-2S) + 3(100-S)
Simplify: C=350-3S
Derivative: dC/dS = -3
What this means is that C will decrease by 3 for each increase of S (based on our assumption, at least).
Using the inequalities, maximize S while minimizing the other variables.
S+U≥100 so S=100, U=0, and 2S+T≥50, 200+T≥50, so T=0
Plug into C.
C=200.
Just for some perspective:
s=100, t=0, u=0 >> c=200 (our answer)
s=99, t=0, u=1 >> c=201
s=75, t=0, u=25 >> c=225
s=25, t=0, u=75 >> c=275
s=0, t=50, u=100 >> c=350