Find the inverse function of f(x)= 1/(3x−1)

Answer 1

f(x) = 1/(3x-1)

y = 1/(3x-1)

switch x and y, and solve for the new y

x = 1/(3y-1)

3y-1 = 1/x

3y = 1/x+1

y = (1/x+1)/3 = 1/3x + 1/3

f^-1(x) = 1/3x + 1/3 = the inverse function