This is a differential equation problem.
W'(t) = 0.2e0.1t
dW/dt = 0.2e0.1t
dw = 0.2e0.1t dt
Now you can integrate both.
W(t) = 0.2 [e0.1t/0.1] + C
W(t) = 2 [e0.1t] + C
Now we know W(0) = 4
W(0) = 2e0+C
C = 4-2
C = 2
After t hours, W(t) = 2 e0.1t + 2
After 8 hours, W(8) = 2e0.1*8+2 = 6.45 gram
I hope this helps...