Raymond B. answered 06/30/21
Math, microeconomics or criminal justice
If there were no defects, the cost would be 3,000 x 40 = $120,000
there are an expected zero defective tires in 10% = 0(.1) =0
an expected 1% defective tires in 30% = (0.1)(.3) = .03 x 3000= 90
an expected 2% defective tires in 40% = .02(.4) = .08 x 3000 = 240
an expected 3% defective tires in 20% = .03(.2) = .06 x 3000 = 180
180+240+90 = 510 defective tires
510 x $5 = $2,550 cost for the expected defective tires
3000x40 = $120,000
$120,000 + $2,550 = $122,550 total expected cost for 3000 tires