consider the function f(x,y)= x2y+1 then find 1) f(1,-3) 2) find the domain and range

Answer 1

f(x,y) = (x^2)y + 1

f(1,-3) = (1^2)(-3) + 1 = -3+1 = -2

f(1,-3) =-2

domain and range are any real number, (-inf, +inf)

UNLESS you meant something else by x2y+1. It's ambiguous, and not how people normally write.

maybe you meant x(2y+1) or x/(2y+1) or x/2y + 1 or (x)(2y) + 1 = 2xy+1

then the answers are different