Inactive Tutor answered 06/18/21
Tutor
New to Wyzant
lim(x)→∞ (e3x + 1)/(8 - 4e3x) = lim(x)→∞ (1 + 1/e3x)/(8/e3x - 4) = (1 + 0)/(0 - 4) = - 1/4.
lim(x)→ - ∞ (e3x+ 1)/(8 - 4e3x) = (0 + 1)(8 - 0) = 1/8
Stormee S.
asked 06/18/21Find the limits lim(x)→∞ and lim(x)→−∞ e3x+1÷8−4e3x algebraically.
Inactive Tutor answered 06/18/21
lim(x)→∞ (e3x + 1)/(8 - 4e3x) = lim(x)→∞ (1 + 1/e3x)/(8/e3x - 4) = (1 + 0)/(0 - 4) = - 1/4.
lim(x)→ - ∞ (e3x+ 1)/(8 - 4e3x) = (0 + 1)(8 - 0) = 1/8
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