
Yefim S. answered 06/11/21
Math Tutor with Experience
By rational zeros theorem list of possible rational zeros: ±1, ±2, ±4, ±1/3, ±2/3, ±4/3
By Descard's rule of sighns: 2 or 0 postive zeros (2 changes of sign in y(x))
1 or 1 negative zeros ( 1 change of sign in y(-x))
0 or 2 complex congugate zeros
3x3 - 7x2 + 4 = 0; 3x3 - 3x2- 4x2 + 4 = 0; 3x2(x - 1) - 4(x - 1)(x + 1) = 0; (x - 1)(3x2 - 4x - 4) = 0, x = 1,
3x2 - 4x - 4 = 0; x = (2 ±√4 + 12)/3 = (2 ± 4)/3; x = 2 or x = -2/3
Answer: solutions set {-2/3, 1, 2]