√8x+1 = 5

√5x-4 = 6

√7x-3 -2 = 0 , the -2 is not under the radical sign

√5x^2 - 3x = 2x

√8x+1 = 5

√5x-4 = 6

√7x-3 -2 = 0 , the -2 is not under the radical sign

√5x^2 - 3x = 2x

Tutors, please sign in to answer this question.

^{2} = 5^{2} ---> 8x + 1 = 25 ---> 8x = 24 --->
**x = 2
**√(5x - 4) = 6 ---> (√5x - 4)

√(7x - 3) - 2 = 0 ---> (√(7x - 3))

√(5x

√(5x

(5x

I show you how to do the first. You can try the following problems.

√(8x+1) = 5

Square both sides,

8x+1 = 25

x = 3 <==Answer

I don't understand how you got x=3

Christopher A.

Tutor Expert in ACT, SAT, Math, Writing, Excel, Study Skills and More

Far Rockaway, NY

5.0
(611 ratings)

Robert E.

Experienced Physics and Math Tutor

Jamaica, NY

4.9
(505 ratings)

Steven M.

Premium Test Prep and Subject Tutor - New York City UWS

New York, NY

5.0
(257 ratings)

## Comments

In the first problem, what happened to the 1?

8x+1 was under the radical sign.

Sorry Kristine for misreading the problem you posted. You have to use parentheses v(8x + 1). Even if there is square root from the product you still have to put parentheses, because there is no line above which will indicate the under radical expression.

About 1: it was subtracted from both sides of equation.

Thank you, so much.

You're very welcome, Kristine, but I made mistake, in first equation

x=3.