Calculus Volume and Area

Question

The area of the enclosed area bounded by the curves y = sqrt(x-4), x = 8, y = 0 is...'

a) 8/3

b) 4/3

c) 32/3

d) 16/3

Answer 1

D) 16/3

it's the same area as 4(2) - integral of x^2 evaluated from 0 to 2

= 8 - x^3/3 = 8 - 8/3 = 24/3 - 8/3 = 16/3

transform the graph into y=x^2, it simplifies.