Patrick B. answered 06/08/21
Math and computer tutor/teacher
60 = 2w+L ---> 60 - 2w = L
A = L*w = (60 - 2w)*w
= 60w - 2w^2
0= dA/dw = 60 - 4w
w=15 --> L=30
max rectangle 30 by 15 with area 450
Night S.
asked 06/08/21One side of the garden will be against the barn, so she does not need to put a fence on that side. Find the dimensions of the plot that will maximize the area. What is the maximum area?
Patrick B. answered 06/08/21
Math and computer tutor/teacher
60 = 2w+L ---> 60 - 2w = L
A = L*w = (60 - 2w)*w
= 60w - 2w^2
0= dA/dw = 60 - 4w
w=15 --> L=30
max rectangle 30 by 15 with area 450
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