
Kevin B. answered 06/03/21
Former Teacher and Math Expert
Hello,
I can answer your question about what t and x represent in the Fundamental Theorem of Calculus, Pt. 1. I attempted to write a detailed explanation with pictures in this forum, but it contained too many characters.
Basically, t is what is called a "dummy variable" and represents all numbers between a and b in INTEGRAL[From a to b] f(t) dt. If we allow b to vary, then we will replace b with x and get a new function
F(x) = INTEGRAL[From a to x] f(t) dt.
Recall now that INTEGRAL is the area underneath the curve of f(t). So, in your example of f(t) = t^3 + 1, if I were to graph that function and shade in different regions below that curve, fixing the starting point a, I get different areas. Those different areas are the values of F(x).
The Fundamental Theorem of Calculus, Pt. 1 says this function F(x) is a differentiable function and the derivative of this function (i.e. how much the area below f(t) changes) is no different than just plugging in x for t in f(t). So if I define F(x) = INTEGRAL[From a to x] t^3 + 1 dt and want to find the derivative of this "area function", I can just plug in x for t. So, d/dx F(x) = x^3 +1. This avoids needing to use that limit definition of derivative.
This theorem also shows that computing area and computing speed are opposite operations, like how addition and subtraction are opposite operations.
I think my explanation is better explained with pictures or animations. But in this page, it would take too many characters. If you'd like to discuss this more with me, please feel free to schedule an appointment. I am happy to go over the Fundamental Theorem of Calculus and its proof in greater detail.

Kevin B.
Exactly.06/04/21
Rahul A.
sir still i would like to see your explanation in detail with pictures as you said.but i can't contact you here.is there any other place i can contact you.06/04/21
Rahul A.
sir can you message me coz i am unable to start the conversation.i ll let you know.06/04/21

Kevin B.
You can contact me here: https://www.wyzant.com/Tutors/KevinMath Just send a few dates and times you would be available and we can set up an appointment.06/04/21
Rahul A.
ok i got it thank you sir, you explained it brilliantly. when we take the derivative of integral function(function under the curve), what we get is the height i.e the y-axis as delta x tends to zero, but still we are differentiating with respect to x and here the function is f(t). its it coz the upper bound(upper limit) here is x and that f(x) is in interval a to x, right?06/04/21