Bradford T. answered 06/03/21
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
V= π∫01[5y2]2dy = 25πy5/5|01 = 5π
Michael A.
asked 06/03/21
Bradford T. answered 06/03/21
Retired Engineer / Upper level math instructor
V= π∫01[5y2]2dy = 25πy5/5|01 = 5π
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