Doug C. answered • 06/03/21
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Xani L.
asked • 06/02/21PLEASE HELP!!! - Trig Calculus
Find the derivative of : y = 9csc2(1/3)x
| 1 | -6 csc(1/3)x csc x cot x |
| 2 | -6 csc2(1/3)x cot(1/3)x |
| 3 | -18 csc2(1/3)x cot(1/3)x |
| 4 | 6 csc2(1/3)x cot(1/3)x |
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By chain rule (and working inside out): y' = 9·1/3·-csc1/3xcot1/3x·2csc1/3x = -6csc21/3xcot1/3x
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