|𝐸(𝑥,𝑦)| ≤ 1/2𝑀 (|x−x0| + |y−y0|)2 where M is the upper bound of |fxx| , |fyy| , |fxy| on the rectangle.
fx = 12x + 3y +3
fxx = 12
fxy = 3
fy = 3x + 12y - 3
fyy = 12
M = 12
Thus, for any pt (x,y) such that -.6 ≤ x ≤ 1.4 and -1.6 ≤ y ≤ 2.4 , the linearization of f(x,y), L(x,y), will have a maximum error of 6d4, where d = the distance between (x,y) and (.4 , .4).