Yefim S. answered 05/27/21
Math Tutor with Experience
Slope m of line passing this points m = (0 - 1)/(2 - 0) = -1/2.
Slope of perpendicular line (tangent line) f'(x) = 2 or 4/(1 + 16x2) = 2; 4 = 2 + 32x2; x2 = 1/16; x = ±1/4
Karen D.
asked 05/27/21Find all value(s) of x at which the tangent lines to the graph of f(x)= arctan(4x) are perpendicular to the line which passes through (0, 1) and (2, 0).
Yefim S. answered 05/27/21
Math Tutor with Experience
Slope m of line passing this points m = (0 - 1)/(2 - 0) = -1/2.
Slope of perpendicular line (tangent line) f'(x) = 2 or 4/(1 + 16x2) = 2; 4 = 2 + 32x2; x2 = 1/16; x = ±1/4
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Karen D.
Thank you!05/27/21