Stanton D. answered 05/21/21
Hi Emmanuel A.,
This is indeed a probability problem, not a biology problem!
In particular, you need combinations of failed-seeds and matured-seeds.
Then, you can confidently say that the probability of getting 3 or more mature plants =
1 - [P(0 matured plants) +P(1 matured plant) + P(2 matured plants)]
So what are the combinations? They are the data on failed vs. matured plants.
so P(0 matured plants) = 0.999^3000 ~ 0.04971
P(1 matured plant) = 0.999^2999 * (0.001)^1 * (3000)!/((2999)!(1)!) ~ 0.14928
P(2 matured plants) = 0.999^2998 * (0.001)^2 * (3000)!/((2998)!2!) ~ 0.22408
You should be able to deduce the format of each calculation here, it is P(each failed)^(#failed) *P(each matured)^(#matured) * ways of getting that mix as a combination, that is =(#total)! / ((#failed)!(#matured)!)
The rest of the problem is solved similarly.
Incidentally, this is an abysmal rate of seedling success, assuming the biologist is working in a greenhouse, i.e. cold-stratifying the seeds (or whatever program they need), germinating, and cultivating. And if the biologist is putting them out in the field, in adverse conditions, that wouldn't necessarily reflect the natural process of self-seeding. AND, if the biologist is intending to preserve the species by this program, 3 plants is far too few to ensure genetic diversity preservation. Just sayin'.
-- Cheers, --Mr. d.