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Question

A spinner has 10 equally sized sections,6 of which are gray and 4 of which are blue.The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue?

Answer 1

The question asks for the probability of two events:

1. The 1st spin lands on gray
2. The 2nd spin lands on blue

Because the question used the phrase "and", both events must be satisfied for the condition to be met - as such, we will multiply the probabilities for the individual events.

It's given in the problem that there are 10 equally sized sections - 6 gray and 4 blue. As such, we can derive the following:

1. The probability of ANY spin landing on gray is 6/10, 3/5, or 60%
2. The probability of ANY spin landing on blue is 4/10, 2/5, or 40%

With this knowledge, we know that the first spin being gray has probability 3/5, and the second being blue has probability 2/5. Multiplying these together, we get the result 3/5 * 2/5 = 6/25, or 24%.