Raymond B. answered 05/10/21
Math, microeconomics or criminal justice
f(z) = z^5 + (e^z)(lnz)
f'(z) = 5z^4 +(e^z)(1/z) + (lnz)(e^z)
derivative = f'(z) = 5z^4 + e^z(1/z + lnz)
derivative of (e^z)(lnz) is the derivative of a product. It's the derivative of the 1st term (e^z) times the 2nd term, plus the derivative of the 2nd term (lnz) times the 1st term. [lnz(e^z)]' = lnz(e^z) + e^z(1/z)
derivative of 5z^4 follows the general rule that ax^b has derivative abx^(b-1)
so z^5 has derivative 5z^5-1) = 5z^4
e^z has itself as the derivative (e^z)' = e^z
lnz has 1/x as the derivative