How long are the bases of a trapezoid with an area of 65 square feet and a height of 10 feet if Base Two is one less than twice Base One?

Answer 1

A_trap = [(b₁ + b₂) / 2]·h = 65

[(b₁ + 2b₁ - 1) / 2]·10 = 65

3b₁ - 1 = 13

b₁ = 14/3 , b₂ = 25/3